The length of a rectangle is 4 feet shorter than its width. the area of the rectangle is 42 square feet. find the length and width. round your answer to the nearest tenth of a foot
Accepted Solution
A:
Let the length of the rectangle to be a value, x.
Since you are told that the length is 4 feet shorter than width, then, this can only mean that width = (x+4) The area of a rectangle = length × width. = x(x+4) = 42 =x² + 4x=42 From here form the quadratic equation then solve it to get the value of x (length of the rectangle)
x²+4x-42=0 Using the quadratic formula,
x = -4 + or - (√(16-4×1×-42))÷2
At this point I had a problem with inserting an equation in this platform. So, i have done it have attached a file that explains the above statement. Kindly find it in the attachment below.
x = (-4+or - 13.56)÷2 = 9.56÷2 =4.78 feet The length to the nearest foot = 5 feet. The width to the nearest foot = 5+4 = 9 feet.