A ship sails from harbour h on a bearing of 084 for 340 km until it reaches point P. It the sails on a bearing of 210 for 160km until it reaches point Q. Calculate distance between point Q and harbor. ( Please help me find angle P, i do not know if I need to ise angle 210 to solve for QH)

Answer:QH = 227.8 km ≅ 228 kmStep-by-step explanation:∵ The bearing from H to P is 084°∵ The bearing from P to Q is 210°∵ The distance from H to P = 340 km∵ The distance from P to Q = 160 km∴ The angle between 340 and 160 = 360 - 210 - (180 - 84) = 54°( 180 - 84) ⇒ interior supplementaryBy using cos Rule:(QH)² = (PH)² + (PQ)² - 2(PH)(PQ)cos∠HPQ(QH)² = 340² + 160² - 2(340)(160)cos(54) = 51904.965∴ QH = 227.8 km ≅ 228 km